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Python程序:尋找元組中最大項(xiàng)

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編寫一個(gè) Python 程序來(lái)查找元組中最大或最大的項(xiàng)。這里,我們使用 Tuple max 函數(shù)返回最大的 Tuple 項(xiàng)。

# Tuple Max Item

mxTuple = (3, 78, 67, 34, 88, 11, 23, 19)
print("Tuple Items = ", mxTuple)

print("Largest Item in mxTuple Tuple = ", max(mxTuple))

尋找元組中最大項(xiàng)目的 Python 程序。

我們使用元組排序函數(shù)(sorted(mxTuple))以升序?qū)υM進(jìn)行排序。接下來(lái),我們打印最后一個(gè)索引位置項(xiàng),它是最大的。

# Tuple Max Item

mxTuple = (2, 14, 11, 19, 25, 17, 33, 22, 30) 
print("Tuple Items = ", mxTuple)

mxTuple = sorted(mxTuple)
print("Largest Item in mxTuple Tuple = ", mxTuple[len(mxTuple) - 1])
Tuple Items =  (2, 14, 11, 19, 25, 17, 33, 22, 30)
Largest Item in mxTuple Tuple =  33

在這個(gè) Python 示例中,我們將 Tuple 第一個(gè)值指定為最大值(Tuple maximum = mxTuple[0]),for 循環(huán)范圍從 1 開(kāi)始,遍歷到 mxTuple 長(zhǎng)度。if 條件(if(最大值< mxTuple[I])) examines whether the current 元組項(xiàng)大于最大值。如果為真,則將該元組值賦給最大值,并將索引值賦給最大值變量。

# Tuple Max Item

mxTuple = (25, 17, 19, 33, 55, 22, 40, 30, 50, 29) 
print("Tuple Items = ", mxTuple)

tupLargest = mxTuple[0]
for i in range(1, len(mxTuple)):
    if(tupLargest < mxTuple[i]):
        tupLargest = mxTuple[i]
        tupLargestPos = i

print("Largest Item in mxTuple Tuple     = ", tupLargest)
print("Largest Tuple Item index Position = ", tupLargestPos)
Tuple Items =  (25, 17, 19, 33, 55, 22, 40, 30, 50, 29)
Largest Item in mxTuple Tuple     =  55
Largest Tuple Item index Position =  4

使用函數(shù)打印最大元組數(shù)的 Python 程序。

# Tuple Max Item

def tupleLargest(mxTuple):
    tupLargest = mxTuple[0]
    for i in mxTuple:
        if(tupLargest < i):
            tupLargest = i
    return tupLargest

mxTuple = (19, 25, 77, 56, 89, 45, 55, 12) 
print("Tuple Items = ", mxTuple)

lar = tupleLargest(mxTuple)
print("Largest Item in mxTuple Tuple = ", lar)
Tuple Items =  (19, 25, 77, 56, 89, 45, 55, 12)
Largest Item in mxTuple Tuple =  89

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